(x^2-6x=9)(9x^2-6x+1)

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Solution for (x^2-6x=9)(9x^2-6x+1) equation: 



(x^2-6x=9)(9x^2-6x+1)

We move all terms to the left:

(x^2-6x-(9)(9x^2-6x+1))=0



We calculate terms in parentheses: +(x^2-6x-9(9x^2-6x+1)), so:

x^2-6x-9(9x^2-6x+1)

We multiply parentheses

x^2-81x^2-6x+54x-9

We add all the numbers together, and all the variables

-80x^2+48x-9

Back to the equation:

+(-80x^2+48x-9)



We get rid of parentheses

-80x^2+48x-9=0

a = -80; b = 48; c = -9;
Δ = b2-4ac
Δ = 482-4·(-80)·(-9)
Δ = -576
Delta is less than zero, so there is no solution for the equation

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